Optimal. Leaf size=697 \[ -\frac {\sqrt {a-i b} (i A+B-i C) (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {\sqrt {a+i b} (i A-B-i C) (c+i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{64 b^{7/2} d^{3/2} f}+\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f} \]
[Out]
________________________________________________________________________________________
Rubi [A]
time = 7.54, antiderivative size = 697, normalized size of antiderivative = 1.00, number of steps
used = 16, number of rules used = 8, integrand size = 49, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.163, Rules used = {3728, 3736,
6857, 65, 223, 212, 95, 214} \begin {gather*} -\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (2 B d+5 c C)+2 a^2 b^2 d^2 \left (8 d^2 (A-C)+20 B c d+15 c^2 C\right )-4 a b^3 d \left (40 c d^2 (A-C)+30 B c^2 d-16 B d^3+5 c^3 C\right )+b^4 \left (-240 c^2 d^2 (A-C)+128 d^4 (A-C)-40 B c^3 d+320 B c d^3+5 c^4 C\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{64 b^{7/2} d^{3/2} f}+\frac {\sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2} \left (48 b d^2 (a B+A b-b C)-5 (b c-a d) (-a C d-8 b B d+b c C)\right )}{96 b^2 d f}+\frac {\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)} \left (64 b^2 d^2 (a A d+a B c-a C d+A b c-b B d-b c C)+(b c-a d) \left (48 b d^2 (a B+A b-b C)-5 (b c-a d) (-a C d-8 b B d+b c C)\right )\right )}{64 b^3 d f}-\frac {\sqrt {a-i b} (c-i d)^{5/2} (i A+B-i C) \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {\sqrt {a+i b} (c+i d)^{5/2} (i A-B-i C) \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {(-a C d-8 b B d+b c C) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f} \end {gather*}
Antiderivative was successfully verified.
[In]
[Out]
Rule 65
Rule 95
Rule 212
Rule 214
Rule 223
Rule 3728
Rule 3736
Rule 6857
Rubi steps
\begin {align*} \int \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2} \left (A+B \tan (e+f x)+C \tan ^2(e+f x)\right ) \, dx &=\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\int \frac {(c+d \tan (e+f x))^{5/2} \left (\frac {1}{2} (-b c C+a (8 A-7 C) d)+4 (A b+a B-b C) d \tan (e+f x)-\frac {1}{2} (b c C-8 b B d-a C d) \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx}{4 d}\\ &=-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\int \frac {(c+d \tan (e+f x))^{3/2} \left (\frac {1}{4} (-6 b c (b c C-a (8 A-7 C) d)+(b c+5 a d) (b c C-8 b B d-a C d))+12 b d (A b c+a B c-b c C+a A d-b B d-a C d) \tan (e+f x)+\frac {1}{4} \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx}{12 b d}\\ &=\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\int \frac {\sqrt {c+d \tan (e+f x)} \left (\frac {3}{8} \left (5 a^3 C d^3-a^2 b d^2 (15 c C+8 B d)-b^3 c \left (5 c^2 C+24 B c d+16 (A-C) d^2\right )+a b^2 d \left (64 A c^2-49 c^2 C-96 B c d-48 A d^2+48 C d^2\right )\right )+24 b^2 d \left (2 a A c d-2 a c C d+A b \left (c^2-d^2\right )+a B \left (c^2-d^2\right )-b \left (c^2 C+2 B c d-C d^2\right )\right ) \tan (e+f x)+\frac {3}{8} \left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \tan ^2(e+f x)\right )}{\sqrt {a+b \tan (e+f x)}} \, dx}{24 b^2 d}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\int \frac {-\frac {3}{16} \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )+b^4 c \left (5 c^3 C+88 B c^2 d+144 c (A-C) d^2-64 B d^3\right )+4 a b^3 d \left (27 c^3 C+66 B c^2 d-56 c C d^2-16 B d^3-8 A \left (4 c^3-7 c d^2\right )\right )\right )+24 b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right ) \tan (e+f x)-\frac {3}{16} \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \tan ^2(e+f x)}{\sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}} \, dx}{24 b^3 d}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\text {Subst}\left (\int \frac {-\frac {3}{16} \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )+b^4 c \left (5 c^3 C+88 B c^2 d+144 c (A-C) d^2-64 B d^3\right )+4 a b^3 d \left (27 c^3 C+66 B c^2 d-56 c C d^2-16 B d^3-8 A \left (4 c^3-7 c d^2\right )\right )\right )+24 b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right ) x-\frac {3}{16} \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) x^2}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{24 b^3 d f}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\text {Subst}\left (\int \left (-\frac {3 \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right )}{16 \sqrt {a+b x} \sqrt {c+d x}}+\frac {24 \left (-b^3 d \left (a \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3-A \left (c^3-3 c d^2\right )\right )+b \left ((A-C) d \left (3 c^2-d^2\right )+B \left (c^3-3 c d^2\right )\right )\right )+b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right ) x\right )}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )}\right ) \, dx,x,\tan (e+f x)\right )}{24 b^3 d f}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\text {Subst}\left (\int \frac {-b^3 d \left (a \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3-A \left (c^3-3 c d^2\right )\right )+b \left ((A-C) d \left (3 c^2-d^2\right )+B \left (c^3-3 c d^2\right )\right )\right )+b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right ) x}{\sqrt {a+b x} \sqrt {c+d x} \left (1+x^2\right )} \, dx,x,\tan (e+f x)\right )}{b^3 d f}-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{128 b^3 d f}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\text {Subst}\left (\int \left (\frac {-b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right )-i b^3 d \left (a \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3-A \left (c^3-3 c d^2\right )\right )+b \left ((A-C) d \left (3 c^2-d^2\right )+B \left (c^3-3 c d^2\right )\right )\right )}{2 (i-x) \sqrt {a+b x} \sqrt {c+d x}}+\frac {b^3 d \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right )-i b^3 d \left (a \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3-A \left (c^3-3 c d^2\right )\right )+b \left ((A-C) d \left (3 c^2-d^2\right )+B \left (c^3-3 c d^2\right )\right )\right )}{2 (i+x) \sqrt {a+b x} \sqrt {c+d x}}\right ) \, dx,x,\tan (e+f x)\right )}{b^3 d f}-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \text {Subst}\left (\int \frac {1}{\sqrt {c-\frac {a d}{b}+\frac {d x^2}{b}}} \, dx,x,\sqrt {a+b \tan (e+f x)}\right )}{64 b^4 d f}\\ &=\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\left ((i a+b) (A-i B-C) (c-i d)^3\right ) \text {Subst}\left (\int \frac {1}{(i+x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 f}+\frac {\left ((i a-b) (A+i B-C) (c+i d)^3\right ) \text {Subst}\left (\int \frac {1}{(i-x) \sqrt {a+b x} \sqrt {c+d x}} \, dx,x,\tan (e+f x)\right )}{2 f}-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \text {Subst}\left (\int \frac {1}{1-\frac {d x^2}{b}} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{64 b^4 d f}\\ &=-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{64 b^{7/2} d^{3/2} f}+\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\left ((i a+b) (A-i B-C) (c-i d)^3\right ) \text {Subst}\left (\int \frac {1}{-a+i b-(-c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{f}+\frac {\left ((i a-b) (A+i B-C) (c+i d)^3\right ) \text {Subst}\left (\int \frac {1}{a+i b-(c+i d) x^2} \, dx,x,\frac {\sqrt {a+b \tan (e+f x)}}{\sqrt {c+d \tan (e+f x)}}\right )}{f}\\ &=-\frac {\sqrt {a-i b} (i A+B-i C) (c-i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c-i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a-i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {\sqrt {a+i b} (B-i (A-C)) (c+i d)^{5/2} \tanh ^{-1}\left (\frac {\sqrt {c+i d} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+i b} \sqrt {c+d \tan (e+f x)}}\right )}{f}-\frac {\left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c+d \tan (e+f x)}}\right )}{64 b^{7/2} d^{3/2} f}+\frac {\left (64 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)+(b c-a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{64 b^3 d f}+\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{96 b^2 d f}-\frac {(b c C-8 b B d-a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{24 b d f}+\frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}\\ \end {align*}
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Mathematica [A]
time = 8.41, size = 1261, normalized size = 1.81 \begin {gather*} \frac {C \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{7/2}}{4 d f}+\frac {\frac {(-b c C+8 b B d+a C d) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{5/2}}{6 b f}+\frac {\frac {\left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right ) \sqrt {a+b \tan (e+f x)} (c+d \tan (e+f x))^{3/2}}{8 b f}+\frac {\frac {\left (24 b^2 d^2 (A b c+a B c-b c C+a A d-b B d-a C d)-\frac {3}{8} (-b c+a d) \left (48 b (A b+a B-b C) d^2-5 (b c-a d) (b c C-8 b B d-a C d)\right )\right ) \sqrt {a+b \tan (e+f x)} \sqrt {c+d \tan (e+f x)}}{b f}+\frac {-\frac {24 b^3 d \left (\sqrt {-b^2} \left (b (A-C) d \left (3 c^2-d^2\right )+b B \left (c^3-3 c d^2\right )-a \left (A c^3-c^3 C-3 B c^2 d-3 A c d^2+3 c C d^2+B d^3\right )\right )-b \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {-c+\frac {\sqrt {-b^2} d}{b}} \sqrt {a+b \tan (e+f x)}}{\sqrt {-a+\sqrt {-b^2}} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {-a+\sqrt {-b^2}} \sqrt {-c+\frac {\sqrt {-b^2} d}{b}}}-\frac {24 b^3 d \left (\sqrt {-b^2} \left (b (A-C) d \left (3 c^2-d^2\right )+b B \left (c^3-3 c d^2\right )-a \left (A c^3-c^3 C-3 B c^2 d-3 A c d^2+3 c C d^2+B d^3\right )\right )+b \left (A \left (b c^3+3 a c^2 d-3 b c d^2-a d^3\right )-b \left (c^3 C+3 B c^2 d-3 c C d^2-B d^3\right )+a \left (B c^3-3 c^2 C d-3 B c d^2+C d^3\right )\right )\right ) \tanh ^{-1}\left (\frac {\sqrt {c+\frac {\sqrt {-b^2} d}{b}} \sqrt {a+b \tan (e+f x)}}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+d \tan (e+f x)}}\right )}{\sqrt {a+\sqrt {-b^2}} \sqrt {c+\frac {\sqrt {-b^2} d}{b}}}-\frac {3 \sqrt {b} \sqrt {c-\frac {a d}{b}} \sqrt {\frac {1}{\frac {c}{c-\frac {a d}{b}}-\frac {a d}{b \left (c-\frac {a d}{b}\right )}}} \sqrt {\frac {c}{c-\frac {a d}{b}}-\frac {a d}{b \left (c-\frac {a d}{b}\right )}} \left (5 a^4 C d^4-4 a^3 b d^3 (5 c C+2 B d)+2 a^2 b^2 d^2 \left (15 c^2 C+20 B c d+8 (A-C) d^2\right )-4 a b^3 d \left (5 c^3 C+30 B c^2 d+40 c (A-C) d^2-16 B d^3\right )+b^4 \left (5 c^4 C-40 B c^3 d-240 c^2 (A-C) d^2+320 B c d^3+128 (A-C) d^4\right )\right ) \sinh ^{-1}\left (\frac {\sqrt {d} \sqrt {a+b \tan (e+f x)}}{\sqrt {b} \sqrt {c-\frac {a d}{b}} \sqrt {\frac {c}{c-\frac {a d}{b}}-\frac {a d}{b \left (c-\frac {a d}{b}\right )}}}\right ) \sqrt {\frac {c+d \tan (e+f x)}{c-\frac {a d}{b}}}}{8 \sqrt {d} \sqrt {c+d \tan (e+f x)}}}{b^2 f}}{2 b}}{3 b}}{4 d} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 180.00, size = 0, normalized size = 0.00 \[\int \sqrt {a +b \tan \left (f x +e \right )}\, \left (c +d \tan \left (f x +e \right )\right )^{\frac {5}{2}} \left (A +B \tan \left (f x +e \right )+C \left (\tan ^{2}\left (f x +e \right )\right )\right )\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F(-1)] Timed out
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Timed out} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \int \sqrt {a + b \tan {\left (e + f x \right )}} \left (c + d \tan {\left (e + f x \right )}\right )^{\frac {5}{2}} \left (A + B \tan {\left (e + f x \right )} + C \tan ^{2}{\left (e + f x \right )}\right )\, dx \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.00 \begin {gather*} \int \sqrt {a+b\,\mathrm {tan}\left (e+f\,x\right )}\,{\left (c+d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{5/2}\,\left (C\,{\mathrm {tan}\left (e+f\,x\right )}^2+B\,\mathrm {tan}\left (e+f\,x\right )+A\right ) \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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